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Python def function


Answer is :- A)20

Let's break down how it works step by step: 1. The `func` function is defined with a `try` block and a `finally` block. 2. Within the `try` block, there is a `return` statement that returns the value `10`. However, this `return` statement is within the `try` block. 3. Inside the `finally` block, there is another `return` statement that returns the value `20`. The `finally` block is guaranteed to execute, regardless of whether an exception is raised or not. 4. The `func` function is called using `print(func())`. Now, let's understand how the code behaves: 👉 When the `func` function is called, it starts executing the code within the `try` block. 👉 It encounters the `return 10` statement and prepares to return the value 10. 👉 However, before it actually returns the value, it reaches the `finally` block because of the `finally` keyword. 👉 Inside the `finally` block, it encounters the `return 20` statement, and this statement takes precedence. 👉 The `return 20` statement in the `finally` block causes the function to immediately exit and return the value 20. As a result, when you call `func()`, it returns 20, and you see "20" printed to the console. In a `try...finally` construct, if a `return` statement exists in both the `try` block and the `finally` block, the one in the `finally` block will take precedence and be the final return value.

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